Skip to main content

Circular Measure and Radian

Subject: Additional Mathematics
Topic: 6
Cambridge Code: 4037 / 0606


Radian Measure

Radian - Unit of angle measurement based on arc length

Definition

One radian is the angle subtended at the center of a circle when the arc length equals the radius

1 radian=arc lengthradius1 \text{ radian} = \frac{\text{arc length}}{\text{radius}}

Converting Between Degrees and Radians

π radians=180°\pi \text{ radians} = 180°

1 radian=180°π57.3°1 \text{ radian} = \frac{180°}{\pi} \approx 57.3°

1°=π180 radians1° = \frac{\pi}{180} \text{ radians}

Conversion Formulas: Radians=Degrees×π180\text{Radians} = \text{Degrees} \times \frac{\pi}{180}

Degrees=Radians×180π\text{Degrees} = \text{Radians} \times \frac{180}{\pi}

Common Angles

DegreesRadians
0
30°π6\frac{\pi}{6}
45°π4\frac{\pi}{4}
60°π3\frac{\pi}{3}
90°π2\frac{\pi}{2}
180°π\pi
360°2π2\pi

Arc Length

Arc Length - Distance along the circumference

Formula (with angle in radians)

s=rθs = r\theta

where:

  • ss is arc length
  • rr is radius
  • θ\theta is angle in radians

Example

Find arc length when radius is 5 cm and angle is π3\frac{\pi}{3} radians:

s=5×π3=5π35.24 cms = 5 \times \frac{\pi}{3} = \frac{5\pi}{3} \approx 5.24 \text{ cm}

Formula (with angle in degrees)

s=θ360°×2πr=θπ180×rs = \frac{\theta}{360°} \times 2\pi r = \frac{\theta\pi}{180} \times r


Sector Area

Sector - Region bounded by two radii and an arc

Formula (with angle in radians)

A=12r2θA = \frac{1}{2}r^2\theta

where:

  • AA is sector area
  • rr is radius
  • θ\theta is angle in radians

Example

Find sector area when radius is 4 m and angle is π6\frac{\pi}{6} radians:

A=12(4)2×π6=12×16×π6=8π38.38 m2A = \frac{1}{2}(4)^2 \times \frac{\pi}{6} = \frac{1}{2} \times 16 \times \frac{\pi}{6} = \frac{8\pi}{3} \approx 8.38 \text{ m}^2

Formula (with angle in degrees)

A=θ360°×πr2A = \frac{\theta}{360°} \times \pi r^2


Segment Area

Segment - Region bounded by a chord and an arc

Formula

Asegment=AsectorAtriangleA_{\text{segment}} = A_{\text{sector}} - A_{\text{triangle}}

=12r2θ12r2sinθ= \frac{1}{2}r^2\theta - \frac{1}{2}r^2\sin\theta

=12r2(θsinθ)= \frac{1}{2}r^2(\theta - \sin\theta)

where θ\theta is in radians

Example

Find segment area when r=6r = 6 cm and θ=π3\theta = \frac{\pi}{3}:

A=12(36)(π3sinπ3)A = \frac{1}{2}(36)\left(\frac{\pi}{3} - \sin\frac{\pi}{3}\right)

=18(π332)= 18\left(\frac{\pi}{3} - \frac{\sqrt{3}}{2}\right)

=6π932.18 cm2= 6\pi - 9\sqrt{3} \approx 2.18 \text{ cm}^2


Angles in Standard Position

Standard Position - Angle measured counterclockwise from positive x-axis

Coterminal Angles

Angles that differ by multiples of 2π2\pi radians (or 360°)

Example: π4\frac{\pi}{4} and π4+2π=9π4\frac{\pi}{4} + 2\pi = \frac{9\pi}{4} are coterminal

Reference Angle

Acute angle between terminal side and x-axis

Used to find trigonometric ratios in any quadrant


Circular Functions

Angular Velocity - Rate of change of angle

ω=θt (radians per unit time)\omega = \frac{\theta}{t} \text{ (radians per unit time)}

Linear Velocity: v=rωv = r\omega

Example

A wheel of radius 30 cm rotates at 20 rpm (revolutions per minute).

Find angular velocity in rad/s: ω=20 rev/min=20×2π60=2π3 rad/s2.09 rad/s\omega = 20 \text{ rev/min} = 20 \times \frac{2\pi}{60} = \frac{2\pi}{3} \text{ rad/s} \approx 2.09 \text{ rad/s}

Find linear velocity of point on rim: v=rω=0.3×2π3=0.2π m/s0.628 m/sv = r\omega = 0.3 \times \frac{2\pi}{3} = 0.2\pi \text{ m/s} \approx 0.628 \text{ m/s}


Key Points to Remember

  1. Radian is more natural for circles than degrees
  2. π\pi radians = 180°
  3. Arc length: s=rθs = r\theta (angle in radians)
  4. Sector area: A=12r2θA = \frac{1}{2}r^2\theta (angle in radians)
  5. Segment area: A=12r2(θsinθ)A = \frac{1}{2}r^2(\theta - \sin\theta)
  6. Angles in standard position measured counterclockwise

Worked Examples

Example 1: Convert Degrees to Radians

Convert 225° to radians: 225°=225°×π180°=225π180=5π4 radians225° = 225° \times \frac{\pi}{180°} = \frac{225\pi}{180} = \frac{5\pi}{4} \text{ radians}

Example 2: Arc Length

A circle has radius 8 cm. Find the arc length of a sector with angle 2π5\frac{2\pi}{5} radians:

s=rθ=8×2π5=16π510.05 cms = r\theta = 8 \times \frac{2\pi}{5} = \frac{16\pi}{5} \approx 10.05 \text{ cm}

Example 3: Sector Area

Find the area of a sector with radius 6 m and angle 120°:

First convert: 120°=2π3120° = \frac{2\pi}{3} radians

A=12r2θ=12(36)2π3=12π37.7 m2A = \frac{1}{2}r^2\theta = \frac{1}{2}(36)\frac{2\pi}{3} = 12\pi \approx 37.7 \text{ m}^2


Practice Questions

  1. Convert to radians:

    • 60°
    • 150°
    • 315°
  2. Convert to degrees:

    • π2\frac{\pi}{2}
    • 3π4\frac{3\pi}{4}
    • 5π6\frac{5\pi}{6}
  3. Find arc length and sector area for:

    • r=5r = 5 cm, θ=π6\theta = \frac{\pi}{6}
    • r=10r = 10 m, θ=1.5\theta = 1.5 radians

Revision Tips

  • Practice converting between degrees and radians
  • Remember: s=rθs = r\theta uses angle in radians
  • Sector area: A=12r2θA = \frac{1}{2}r^2\theta (radians)
  • Segment area formula includes subtraction of triangle
  • Draw diagrams to visualize sectors and segments